2x^2-12=-14x

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Solution for 2x^2-12=-14x equation:



2x^2-12=-14x
We move all terms to the left:
2x^2-12-(-14x)=0
We get rid of parentheses
2x^2+14x-12=0
a = 2; b = 14; c = -12;
Δ = b2-4ac
Δ = 142-4·2·(-12)
Δ = 292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{292}=\sqrt{4*73}=\sqrt{4}*\sqrt{73}=2\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{73}}{2*2}=\frac{-14-2\sqrt{73}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{73}}{2*2}=\frac{-14+2\sqrt{73}}{4} $

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